Introduction
The program shows sum of cubes of n numbers. By using the formula (n^2)*((n+1)^2)/4 sum of cubes of a number can be calculated. 1^3+2^3+3^3......
#include<stdio.h>
#include<conio.h>
void main()
{
int a,n;
clrscr();
printf("/n Enter a number:");
scanf("%d",&n);
a=((n*n)*((n+1)*(n+1)))/4;
printf("sum of cubes of numbers upto %d is %d",n,a);
getch();
}
Comments/Suggestions are invited. Happy coding......!
Comments Post a Comment