Introduction
The program shows sum of cubes of n numbers. By using the formula (n^2)*((n+1)^2)/4 sum of cubes of a number can be calculated. 1^3+2^3+3^3......
#include<stdio.h> #include<conio.h> void main() { int a,n; clrscr(); printf("/n Enter a number:"); scanf("%d",&n); a=((n*n)*((n+1)*(n+1)))/4; printf("sum of cubes of numbers upto %d is %d",n,a); getch(); }
Comments/Suggestions are invited. Happy coding......!
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