Introduction
The program shows the sum of n natural numbers. A number should be entered by the user, if 10 entered sum first 10 natural numbers can be calculated. By using the formula (n*(n+1))/2 sum of natural numbers can be calculated.
#include<stdio.h>
#include<conio.h>
void main()
{
int a,n;
printf("/n Enter a number");
scanf("%d",&n);
a=(n*(n+1))/2;
printf("Sum of natural numbers upto %d is %d",n,a);
getch();
}
Comments/Suggestions are invited. Happy coding......!
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