Introduction
The program shows the sum of n natural numbers. A number should be entered by the user, if 10 entered sum first 10 natural numbers can be calculated. By using the formula (n*(n+1))/2 sum of natural numbers can be calculated.
#include<stdio.h> #include<conio.h> void main() { int a,n; printf("/n Enter a number"); scanf("%d",&n); a=(n*(n+1))/2; printf("Sum of natural numbers upto %d is %d",n,a); getch(); }
Comments/Suggestions are invited. Happy coding......!
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